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[Articles Home]  [Add Article]  

Bandwidth versus Keying Speed

Mickey Cox (K5MC) on May 26, 2007
View comments about this article!


Bandwidth versus Keying Speed

Introduction

A popular article on this reflector says that it is a "misconception" that the "bandwidth" of a CW transmitter is a function of the keying speed. On the other hand, The ARRL Handbook says that the keying speed is a factor in determining the bandwidth "occupied" by a CW signal. What's going on here?

Although there are a variety of potential pitfalls when discussing this topic, the most obvious one is the meaning of the word "bandwidth" itself. Many definitions of bandwidth exist and it is important that the precise definition or type of signal bandwidth be made clear early on.

Fourier Analysis of Signals

I will focus here on the "power" bandwidth of a CW transmitter when keyed by a long string of dits. According to Couch [1], the power bandwidth is f2 - f1, where f1 < f < f2 defines the frequency band in which 99% of the total average power resides. Note that this definition is similar to the FCC's definition of "occupied" bandwidth:

Occupied bandwidth. The frequency bandwidth such that, below its lower and above its upper frequency limits, the mean powers radiated are each equal to 0.5 percent of the total mean power radiated by a given emission [2].

In studying the specific waveforms presented here, I have used classical Fourier analysis as described in practically all of the communication systems and signal analysis textbooks written over the past 50 years or more.

Let's start with a very good keying wave shape, a sinusoidal-shaped pulse with identical rise and fall times of 5 milliseconds as shown in Figure 1. Now let's assume we form a periodic signal using these shaped pulses with a duty cycle of 50% to represent a long string of dits. Since we want to maintain the same rise/fall characteristics (shapes and times) regardless of speed, we will only vary the time duration of the constant amplitude portion of each pulse (designated as tc) to increase or decrease the number of dits sent per second. I have chosen two specific speeds here, 2.4 words per minute (wpm) and 30 wpm. These speeds were convenient choices mathematically and are also considered to be reasonably representative of the speed range employed by many hams. The value of tc is 0.490 seconds and 0.030 seconds for 2.4 wpm and 30 wpm, respectively. (These values of tc were found by first determining that the number of dits per second is 1 and 12.5 for 2.4 wpm and 30 wpm, respectively.)

Once the exact keying waveform has been decided, the detailed Fourier analysis can begin. If a periodic pulse signal is assumed for the keying waveform, one can calculate its Fourier series and the resulting average power (on a 1-ohm basis) for each discrete frequency component. Once the frequency characteristics of the keying waveform (which is the modulating signal) are known, the frequency characteristics of the radiated CW signal (which, mathematically, is binary ASK) can be found via trigonometric identities because the output signal is the product of the modulating signal and the high frequency carrier.

It turns out that the 99.1% power bandwidth of the 2.4-wpm CW/ASK signal is 34 Hz for the 5-ms sinusoidal-shaped keying waveform. (That is, 99.1% of the total power in the 2.4-wpm CW signal is contained by the carrier and the first 17 sideband pairs.) However, the 99.1% power bandwidth of the 30-wpm CW signal is 150 Hz. (99.1% of the total power in the 30-wpm CW signal is contained by the carrier and the first 6 sideband pairs.) Even though both signals have exactly the same rise and fall characteristics, Fourier analysis indicates that the 99.1% power bandwidth of the 30-wpm CW signal is over four times as large as that of the 2.4-wpm signal!

0x01 graphic

Figure 1. Sinusoidal keying waveform with symmetrical rise and fall times

Now suppose our keying waveform is changed from the very good one described above to one having zero rise and fall times. "Square-wave" keying is quite a bit easier to examine mathematically than sinusoidal keying and it will yield a "worst-case" value of power bandwidth for a given speed. As before, the speed of the dits is set so that we are sending at a rate of either 2.4 wpm or 30 wpm. In the case of square-wave keying, the 99.1% power bandwidth for our CW signal is 42 Hz and 525 Hz when sending dits at 2.4 wpm and 30 wpm, respectively. Once again we see that the power bandwidth increases significantly in going from 2.4 to 30 wpm. In fact, since both the rise and fall times of this keying waveform are zero, the power bandwidth ratio will be exactly equal to the speed ratio (12.5 to 1 in this specific example). Of course, we also expected the power bandwidth to increase significantly in going from sinusoidal keying to square-wave keying at the same speed. At 2.4 wpm, the 99.1% power bandwidth ratio is 1.24 for the two keying waveforms, but at 30 wpm the ratio is a whopping 3.50. The results are summarized in Table 1 below.

2.4 words per minute

30 words per minute

Sinusoidal keying (5 ms)

34 Hz

150 Hz

Square-wave keying

42 Hz

525 Hz

Table 1. 99.1% power bandwidth for CW/ASK transmitter for periodic signaling

I have purposely avoided cluttering this article with the mathematical details used to obtain the values shown in Table 1. If anyone is interested, I will be glad to post the details in a follow-up article or via email. Although I have carefully checked all of my calculations, in some cases by both time-domain and frequency-domain approaches, there is always the possibility of some computational errors. However, these answers appear to be quite consistent with my expectations and with such sources as The ARRL Handbook.

Summary

The concept of "bandwidth" commonly used in electrical engineering (and certainly used by the FCC in its definition of occupied bandwidth) is a "time averaged" quantity. As shown in Table 1, 99.1% of the total mean (average) power of the 30-wpm signal resides in a wider bandwidth as compared to the 2.4-wpm signal. A crucial point to be made here is that the concept of occupied bandwidth does not say that the strength of the individual key clicks generated by a poorly designed transmitter is reduced when the sending speed is decreased! The information provided by the occupied bandwidth is exactly that described in its definition. In closing, however, I do want to point out that if I have to be subjected to key clicks when operating CW, I would much prefer that the offending transmitter send at a speed of 1 word per 20 minutes rather than 20 words per minute!

References

[1] Leon W. Couch, Digital and Analog Communication Systems, 7th ed., Pearson

Prentice Hall, 2007.

[2] FCC Rules and Regulations, 47 CFR 2.202

Member Comments:
This article has expired. No more comments may be added.
 
Bandwidth versus Keying Speed  
by SM0AOM on May 26, 2007 Mail this to a friend!
By a substantially identical reasoning, the ITU/CCIR
once formulated the "necessary bandwidth" formulas
in the Radio Regulations.

For A1A emission or "on/off telegraphy" it reads

Bn = BK

where Bn = necessary bandwidth in Hz
B = keying speed in Bauds
K = factor to accommodate the number of keying sidebands necessary to recreate the shapes of the signal elements. K is usually assumed to be 3 for
"non-fading circuits" or "soft keying", 5 for
"fading circuits" or "hard keying"
It is further assumed that the keying envelope functions are close to optimal.

Using the above formula,
a 20 WPM (16,66 Baud) A1A signal has a necessary bandwidth of 84 Hz for "hard keying" and 50 Hz for "soft keying".

For an in-depth discussion by W9CF of the optimum keying envelope function see
http://fermi.la.asu.edu/w9cf/articles/click/index.html

73/

Karl-Arne
SM0AOM


 
RE: Bandwidth versus Keying Speed  
by W6TH on May 26, 2007 Mail this to a friend!
.
Very interesting.

Bandwidth versus Keying Speed versus my 250 Hz cw Filter.

Very interesting.

W6TH

.:
 
Bandwidth versus Keying Speed  
by N0CTI on May 26, 2007 Mail this to a friend!
Looking at the results in the table I conclude that bandwidth is used more efficiently with soft keying rather than hard keying. Also, with hard keying the bandwidth per word-per-minute is constant; bandwidth is directly proportional to speed. With soft keying, faster speeds use bandwidth more efficiently than slow speeds.

Interesting. Thanks for the article.

Dave K0DCH (eham database is not quite up to date.)
 
RE: Bandwidth versus Keying Speed  
by N4DSP on May 26, 2007 Mail this to a friend!
Congratulations to eHam and the authors of these articles. Its about time. Great learning experience for all. Who said there are no longer any elmers.

73
john-n4dsp
 
Bandwidth versus Keying Speed  
by W8AD on May 26, 2007 Mail this to a friend!

This a great informative article. This is the kind of thing we need on E-HAM. The quality of this article should encourage hams, both new and experienced, that there are very knowledgeable and nice folks out there who make this a great hobby!

Thank you,

Don, W8AD (hope the trolls stay under the bridge on this one!)
 
RE: Bandwidth versus Keying Speed  
by N6XL on May 26, 2007 Mail this to a friend!
OUT-STANDING, we could use more articles like this.

73's
Paul
 
RE: Bandwidth versus Keying Speed  
by W6TH on May 26, 2007 Mail this to a friend!
.
K5MC Mickey,

"Quote Mickey"

In closing, however, I do want to point out that if I have to be subjected to key clicks when operating CW, I would much prefer that the offending transmitter send at a speed of 1 word per 20 minutes rather than 20 words per minute!
................................................

Well my friend, back in the "old days", key clicks never bothered us and speeds were well above 35 wpm just using a bug. Believe me with a few hundred volts across our bugs many time caused key clicks just keying the cathodes of the crystal oscillators. So I say the key clicks never was a problem.

We, back then, wanted very hard keying and not the soft kind as at the softer, higher speeds, (50 wpm) the words were run much closer together and sounded as though there were no spacing. Another thing we copied by the sound of the words and not by characters as is taught today.

So all in all, I still enjoy the hard keying and especially at speeds at 50 and above for nice copy, regardless of key clicks or not.

It was very easy to soften the cw as all we did was to put a 100 ohm resistor in series with the bug and a 1 Mfd capacitor across the resistor and go lower until the op on the other enjoyed the sound.

Key clicks were told to the operator and he worked on the keying until all was accomplished.

Nice article Mickey and hope we get more to elmer the new Amateur Radio Operators, but remember old days used logic and were creative.Now, "Thats Brother Hood".

73, W6TH
.:
 
RE: Bandwidth versus Keying Speed  
by W7ETA on May 26, 2007 Mail this to a friend!
Wow!

A three fer: great prose, coherent, and concise.

Thanks

73
Bob
 
Bandwidth versus Keying Speed  
by K6YE on May 26, 2007 Mail this to a friend!
Mickey,

I echo the other posts. Great article!!!

Semper Fi,

Tommy - K6YE
DX IS
 
RE: Bandwidth versus Keying Speed  
by W8JI on May 26, 2007 Mail this to a friend!
Hi Mickey,

nice article but the bandwidth is actually set by the rise and fall times and shapes, not by the keying speed.

The keying speed only controls the number of times the offending sidebands repeat.

You can see detailed explanations of this on my web page at:

http://www.w8ji.com/keyclicks.htm

This page includes links to W9CF's site and a page with a white paper by Mark Amos.

73 Tom

 
RE: Bandwidth versus Keying Speed  
by W8JI on May 26, 2007 Mail this to a friend!
By the way, most important is the link to W9CF's website where he shows the power distribution of keyclicks (the sidebands) of a CW signal.

Link:

http://fermi.la.asu.edu/w9cf/articles/click/index.html

If you look at the bandwidth distribution you will find the overall shape of the sidebands (attenuation vs. frequency as you tune off higher or lower) is identical with all keying speeds. The only thing that happens is nulls and peaks move around inside that overall shape, but the receiver doesn't know the difference since its filter always has to be wide enough to pass all the sidebands.

The W9CF and other pages and papers dispell the common misconception that overall bandwidth changes with speed. The badwidth ALWAYS has to be wide enough to pass the rising and falling edges of the envelope.

73 Tom
 
RE: Bandwidth versus Keying Speed  
by AA4PB on May 26, 2007 Mail this to a friend!
Tom, is that because the keying speed on any normal CW signal is slow enough that the shape of the rise and fall times is the major contributor to bandwidth? As the speed countinues to rise (as in 300 baud, for example) then the speed becomes a major contributor to bandwidth? Otherwise it seems that we could run some very high baud rates on HF without worrying about occupied bandwidth.
 
RE: Bandwidth versus Keying Speed  
by W6TH on May 26, 2007 Mail this to a friend!
.
Not much to really discuss on this post because there are two types of key clicks that I remember...One type that was within a few Hz of center frequency and the other type that was up and down the center frequency a few Khz.

Another, we may call it a third one was using a RF amplifier and was caused by poor neutralization of the final amplifier.

I enjoy the keying of a very fast rise time and a slower falloff time, guess it is up to the receiver and the human ear as many have looked good on the osciloscope and yet did not seem to sound so good.

Radios of today are as close as one can get as the majority sound exceptionally good.The outboard keyers also do help the keying even with a different dot to dash ratio.Then again most say the semi breakin sounds better than the full breakin.

..............................Tasters Choice.........

.:
 
RE: Bandwidth versus Keying Speed  
by KE3HO on May 26, 2007 Mail this to a friend!
<<< "is that because the keying speed on any normal CW signal is slow enough that the shape of the rise and fall times is the major contributor to bandwidth?" >>>

Look at it this way: Consider Figure 1 above. The CW keying waveform as shown has three parts, the rise time, the period where the RF output is constant (tc), and the fall time.

During the rise time, the RF output is a time varying signal - in other words, it is a modulated signal. This time-changing signal produces sidebands. The sidebands produced are determined solely by the rise time and the shape of the keying function during the rise time.

During the "tc" period, the RF output is constant - in other words, it is a pure unmodulated carrier. During this period no sidebands are produced. The width of the carrier is set by the stability of the rigs oscillator, power supply stability, etc.

During the fall time, once again the signal is time-varying, so once again sidebands are produced.

How does keying speed play into this? Consider the rise time period. The keying waveform and the rise time are fixed - they do not depend on keying speed. If you don't believe this, they ask yourself the following question: "When I put down the key, how does the rig know how long I am going to hold it down?" See what I am saying? The only way that the rise time and keying waveform could change with keying speed would be if the rig somehow knew how long you were going to hold down the key. It can't. Period. Same goes for the fall time. The fall time and keying waveform are fixed.

Looking at the waveform again, as keying speed increases, the only thing that changes is the middle period, tc. As keying speed increases, tc becomes shorter. However, this is the period where the rig is producing as close to a pure unmodulated carrier as it can. The rise time period and fall time period are not affected by keying speed, so the sidebands that they produce do not change with keying speed.

73 - Jim
 
RE: Bandwidth versus Keying Speed  
by W8JI on May 26, 2007 Mail this to a friend!
by AA4PB on May 26, 2007 Tom, is that because the keying speed on any normal CW signal is slow enough that the shape of the rise and fall times is the major contributor to bandwidth? >>

Picture it this way. When we key the transmitter the waveshape of the envelope changes. That waveshape has a rise time and a fall time, and a slope rate within that time.

With a perfect sine shaped rise and fall time each of .005 seconds, the full cycle takes .01 seconds. It is a 1/.01 = 100Hz sine wave modulating the carrier. This means we have a sideband 100Hz above and 100Hz below the carrier every time the key is closed and every time the key is opened. (This assumes an identical rise and fall waveform.)

We cannot possibly have a narrower signal, or we must lengthen the rise and fall times. As a matter of fact if we ran that signal through a perfect 100Hz bandwidth filter the rise and fall times would simply change to .010 seconds at the output!!!

I've cleaned up transmitters by doing just that.

Even if I just send a single rising edge it will make a sideband above and below the carrier, and the maximum frequency distance away from the carrier would be determined by the rate of change in that rising carrier. It is nothing but AM, an amplitude modulated DSB transmission. The occupied spectrum is always the same if it is one change a second or one change an hour, because the rate and slope of change determines the ultimate bandwidth. The only thing that happens when I send faster is the sidebands appear more often.

The sidebands ALWAYS have to be out further than the keying rate because the keying rate has to always be slower than the rise and fall frequency. You can NEVER send faster than the rise and fall time alolows the carrier to turn off or on!!! That's just common sense.

Because of that, the only thing keying speed does is make it appear like sidebands are moving around inside that spectrum....but that is an illusion of time. Your receiver...just like your ears....has no memory of the leading and trailing edges. Now a storage device, either in mathematical analysis or spectral display, will show those ripples inside the primary shape....but that is because we are looking at time domain modulation of the high frequency sidebands caused by a very low frequency keying signal. It really has no effect on our receiver or our ears.

Doug Smith rewrote the ARRL Handbook's incorrect section on keying. I think Doug Smith KF6DX also has a white paper on the web that explains exactly the same thing as I just described.

The incorrect Handbook information may well have been the reason Yaesu and others put out terrible CW transmitters for many years. Either that or the engineers at those companies misused the fourier analysis and assumed the WIDEST part of the signal was determined by the CW speed. If I send 2 WPM with an unmodified FT1000D you would hear me clicking up and down about 1kHz, and if I sent 50 WPM it would be the same. The clicks would just become more frequent.

Picture a light swicth in your house. You turn it on and you hear a click in an AM radio at 1500kHz. The "carrier" frequency of the light switch is 60 Hz. The sideband is at least 1500kHz away. It's there (and everywhere in between) no matter how fast the light switch is turned off and on. But if we looked at it in a time domain that was much longer than the off and on times it would appear like there were ripples moving around inside the bandwidth, although the overall response would be exactly the same.

A drawing is worth 1000 words, and Dr. Schmidt's (W9CF) analysis shows drawings of what happens. My web page has pictures, or anyone with a storage spectrum analyzer can see the very same thing. Anyone with a receiver can hear the very same thing also.

I really wonder, since everyone can see and hear the same thing, why this same misconception keeps popping up. Especially since the ARRL has now corrected the Handbook and there are so many white papers by so many different unrelated people appearing that explain the same exact result. It is also simple basic logic. A transmitter that requires a certain bandwidth to allow the carrier to turn off and on can become wider or narrower just because we use it once a day, once a minute, once a second, or once every 50 milliseconds. It can only change if we try to turn it off and on faster than the rise and fall allows.

If a transmitter HAS to generate a sideband at least the 1/time of the complete envelope rise and fall cycle above and below the carrier to allow the carrier to move, why do some insist the bandwidth of that transition that causes all the problems suddenly is narrower if we send one dit an hour?

It occurs less frequently, but the sideband is the same bandwidth. You close the key, the signal is so wide during the rise because of the rise modulation of the envelope. You open the key, the sidebands are so wide with such an amplitude based on the fall time and shape. You send faster and it happens more often, but the shape where the trash is generated remains the same and so does the overall bandwidth of the trash.

The CW receiver that it bothers by definition CANNOT remember and store the last rise or fall and add or subtract that energy over enough keying transitions to make the ripples appear. If it did it would never be able to pass the off and on tone, and it would not be useful as a CW receiver.

The flaw in the idea that speed sets bandwidth of a transmitter is the CW keying rate is so much slower than the rise and fall time that it simply doesn't affect what we hear on a receiver. We hear the same click at the same distance regardless of speed so long as the envelope rise and fall doesn't change time or slope, we simply hear it more or less often.

73 Tom
 
RE: Bandwidth versus Keying Speed  
by W8JI on May 26, 2007 Mail this to a friend!
KE3HO,

Thank you Jim.

That's a fresh and correct contribution.

Changing the part of the waveform that is NOT producing sidebands cannot change the width of the sidebands. Very good and very simple.

There are a dozen ways to look at this, but the results are always the same.

73 Tom

 
Bandwidth versus Keying Speed  
by VE3MFN on May 26, 2007 Mail this to a friend!
Very clear and concise, and the great thing is I could read it without feeling like I was about to 'blow out a frontal lobe' on some of the math....!! Great article....

Rick VE3MFN (QRQ nut)
 
Bandwidth versus Keying Speed  
by K5MC on May 27, 2007 Mail this to a friend!
I'm sorry to see that W8JI continues to misunderstand the concept of "power" or "occupied" bandwidth. The mathematical meaning of power bandwidth is quite clear; I was also quite clear in my article that I was reporting on the 99.1% power bandwidth of the various keying waveforms that I considered.

W9CF's conclusion at http://fermi.la.asu.edu/w9cf/articles/click/index.html appears to be ". . . the keying speed does not effect (affect?) the overall bandwidth." I don't believe the term "overall" bandwidth is defined by W9CF or, for that matter, anybody else. I certainly don't recall seeing that term defined in any reputable signal analysis or communications textbook. If W9CF means the "absolute" bandwidth when he says the "overall" bandwidth, then he's clearly wrong, at least according to Fourier analysis. All signals that are limited in time have an absolute bandwidth of infinity.

Now that I've mentioned the article by W9CF, I'm afraid that while his mathematics may appear to be quite impressive, he also appears to not understand a fundamental limitation of Fourier transforms! The basic functions used in Fourier analysis are sine waves and cosine waves; these waves are precisely located in frequency but exist for all time. The frequency information of a signal calculated by the classical Fourier transform is an average over the entire time duration of the signal. (I've basically just quoted a couple of sentences from an engineering journal paper written by one of my graduate students and myself from about 10 years ago.)

If you calculate the Fourier transform of a single square-wave pulse, for example, you will clearly find that the "bandwidth" of that signal varies inversely with its time duration. (This assumes we are using a consistent definition of bandwidth, other than the absolute bandwidth. One possible definition is the 99% energy bandwidth.) I chose to use periodic keying signals in my article rather than single pulses (as assumed by W9CF) because I wanted to illustrate the concept of power bandwidth (essentially the same thing as the FCC's occupied bandwidth.) A periodic keying waveform also allows us to approach the problem via Fourier series rather than Fourier transforms. (The concept of Fourier series is simpler than that of Fourier transforms.)

I welcome anyone with a signal analysis/communications background to check my mathematics. The signal analysis that I discussed in my article (99.1% power bandwidth!) is representative of what a good junior or senior electrical engineering student is able to do after completing a typical signal analysis/communications course. I should know this because I'm an electrical engineering professor and I've taught such courses for over 20 years now.

One final note: If W8JI truly believes that the concept of occupied bandwidth is terribly wrong, then he should come up with his own precise (that is, mathematical) definition of bandwidth for the FCC engineers to consider.

73,
K5MC, Ph.D., P.E.
 
RE: Bandwidth versus Keying Speed  
by SM0AOM on May 27, 2007 Mail this to a friend!
This discussion has split into two parts.

We have the part regarding any emissions outside the "necessary bandwidth"("key clicks") caused by improper shaping of the rise and fall times of the signalling elements.

And another part that deals with the bandwidth necessary to pass the actual information.

It is perfectly acceptable to transmit radiotelegraphy
using sinusodially shaped signal elements (but the signals will be very difficult to read by ear).

In this special case we have 100% AM with a slow modulating waveform, creating a single pair of sidebands that are spaced +/- (keying rate in Baud)/2 [Hz]from the carrier or center frequency.

If the shaping is "perfect" [no discontinuites] the necessary bandwidth will be just the keying rate in Baud; no more , no less.

Convenient aural reception of telegraphy requires the
starting and ending of the signal elements to be more defined than the sinusodial shapes, and if we decrease the rise and fall times to make the elements more distinct, this will create higher order sidebands.

If an operator at the receiving end is satisfied with an element shape that results by incorporating 3 pairs of sidebands, the transmitter shaping can be set to this value and the "necessary bandwidth" becomes 3 times the keying rate in Baud.

"Key clicks" are a completely different matter.
They result from using a transmitter shaping that is not properly related to the signal element duration or keying rate.

The CCIR "necessary bandwidth" formulas have been derived assuming that the transmitter shaping is done in a proper way, and the virtues of using the Gauss Error Function as the shaping function have been known for decades in the professional world.

The spectral masks resulting from this shaping waveform have been used in i.a. type acceptance criteria for point-to-point and marine radio transmitters at least since the 60's.


73/

Karl-Arne
SM0AOM
 
RE: Bandwidth versus Keying Speed  
by W8JI on May 27, 2007 Mail this to a friend!
The problem is some people wrong assume the NECESSARY bandwidth is the ACTUAL bandwidth.

There will always be a few who cling to that mistake no matter how logic and actual measurement or operation dictates otherwise. :-)

All the theory in the world can't change what we hear with our own ears or see with our own eyes with a spectrum analyzer.

73 Tom
 
RE: Bandwidth versus Keying Speed  
by W8JI on May 27, 2007 Mail this to a friend!
http://www.doug-smith.net/cwbandwidth1.htm

Doug Smith says "Fig 2 is a spectral analysis of the waveform of Fig 1. Spectral occupancy is chiefly determined by the envelope shape and not by the keying speed. To be sure, keying such a waveform at high speed puts more energy into adjacent frequencies than at low speed; but the instantaneous amplitude of the keying sidebands is constant during the rise and fall times, regardless of keying speed."

http://fermi.la.asu.edu/w9cf/articles/click/index.html

W9CF says "This problem was brought to my attention by Tom Rauch, W8JI, who, in his note to me, had described his experience and correctly pointed out all the main features that govern the bandwith. These notes are an expanded version of my reply giving the mathematical explanation.
To fit the most CW signals into the available spectrum, we need to limit the bandwidth taken up by the signals. It is therefore useful to see how the energy in a dot or dash pulse is distributed around the carrier frequency. Here I give some notes on how to make this analysis. The main result is that the spectrum for many keying shapes is given by the product of the spectrum of a square pulse times the spectrum of the slope of the rise and fall behavior of the pulse.

It seems from my experience reading morse, that the rise time should be the main factor in producing code that can be read by ear comfortably. Since the rise time dominates the bandwidth for the usual CW signal, the analysis shows that to get a nearly optimal bandwidth to rise time, the keying pulse shape should have a gaussian slope.

In the next section I review basic Fourier analysis of amplitude modulation. I then calculate the spectrum of a pulse with an exponentially shaped rise and fall as would be produced by simple RC networks. The results suggest the more general analysis in the following section, with the conclusion that a pulse with gaussian slope, i.e. error function rise and fall shapes, will have an optimal bandwidth and rise time.

It seems likely that all of this would have been worked out by radio engineers in the early 1900s when CW signals were first employed. "

Both articles are good reading, and common sense will agree with the details in those articles.

73 Tom


 
Bandwidth versus Keying Speed  
by K5MC on May 27, 2007 Mail this to a friend!
It certainly appears to me that W8JI and some other folks on this reflector are assuming that a sinusoid (a sine wave or cosine wave) of frequency f Hz having a finite time duration has its entire spectrum concentrated at f Hz. According to Fourier analysis, at least, such an assumption is wrong! For a sinusoid of finite duration T seconds, the Fourier spectrum is spread out on either side of f Hz by the factor 1/T. In other words, the spectrum (that is, the bandwidth) of a sinusoid is inversely proportional to its time duration.

For example, let's consider two sinusoids of equal amplitude, say 1 volt. Assume that s1 is a 1-kHz sine wave that lasts for exactly 1 second and s2 is a 1-kHz sine wave that lasts for exactly 2 seconds. Therefore, s1 will consist of 1000 successive sine waves, with each wave having an amplitude and period of 1 volt and 1 millisecond, respectively. Similarly, s2 will consist of 2000 successive sine waves, with each wave also having an amplitude and period of 1 volt and 1 millisecond, respectively. The 99% energy bandwidth (just to be specific on my definition of bandwidth here) of s1 will be exactly twice as much as that of s2. By my calculations, the 99% energy bandwidth of s1 is 20.6 Hz and the 99% energy bandwidth of s2 is 10.3 Hz.

The discussion above should remind everyone that the "bandwidth" of an FM signal is not simply equal to twice the maximum deviation. For example, if the maximum deviation of a commercial FM broadcast station is limited to plus or minus 75 kHz, the bandwidth of that FM station is certainly larger than 150 kHz.

I also want to point out that spectrum analyzers are based upon the very principles of Fourier analysis that I've been discussing! Spectrum analyzers provide an approximation of the "exact" Fourier analysis that I have tried to present here. In addition to teaching the theory of signal analysis, I have some modest experience in working with "real world" signals, including such examples as the transient analysis of power engineering waveforms caused by such items as arc furnaces (which are essentially random loads during the early part of a melting cycle) and power transformers (for example, transformer inrush currents).

73, K5MC
 
RE: Bandwidth versus Keying Speed  
by W8JI on May 27, 2007 Mail this to a friend!
Mickey,

I don't know how to explain it any bettter than I and several others have already done.

1.) Bandwidth is required only when the carrier changes level. When at full power or zero power it has no bandwidth, it has no modulation.

2.) Assuming a stable carrier the rate of power level change controls the highest sideband frequency produced. The level change at that slope (or any angle of slope during the transition) controls the amplitude of the sidebands.

3.) The receiver by required function cannot store the repeating sidebands. It has to respond to the very shortest off and on period without dragging the response out or we could not hear the tones starting and stopping.

4.) When we are off frequency with a CW receiver we hear the same exact amplitude level of clicks at the same spacing no matter how fast or slow the signal is keyed. This is because the transmitter ALWAYS has to generate the same badwidth during the upward and downward transition or it simply cannot transmit the shape of the rise and fall!!!

5.) If we look at that over a long time and add the effects of the much lower frequency off and on keying, the effect is to cause ripples or peaks and valleys in the points where energy is distributed. The overall SLOPE of that sideband energy is exactly the same with one dit or a hundred dits per second, just as long as the keying rate does not approach the rise and fall rate.

6.) We cannot sort out those close spaced ripples with a receiver, so they are meaningless to the operator. We cannot sort them out because the bandwidth of the receiver has to be wider than the rise and fall frequency during the rising and falling transitions or the receiver will "mush" the transmitter by clipping sidebands. You can hear this effect as you crank in selectivity on a receiver to values below a few hundred Hz.

7.) A spectrum analyzer will store the signals and as it makes many sweeps will paint the ripples on the screen, but if we look at the envelope shape we will always find the roll off or attenuation with frequency will always match the shape required to produce the rise and fall shape of the keyed signal.

I can't say much more. All it takes is a few minutes with a receiver and a transmitter and you will see what I say above is true. The space we take up on a band with our keyclicks is entirely dependent on the shape of the rising and falling edges.

While it is true the clicks appear more frequently at higher speeds and have more average power over time at higher speeds, the overall shape of the area you bother remains exactly the same independent of keying speeds as long as those speeds are reasonable. Of course if I send one klick an hour no one would care, but if I was 1kHz away and you were sending 5-10 WPM or 50 WPM you would be placing the same energy at each off and on transition on my frequency.

Sending slower will not make this bandwidth go away.

Thinking otherwise is pobably what got Yaesu and others in big trouble. They assumed they could put out rigs with horrible ~1mS rise times.

That's why you can hear an FT1000MP clicking on CW 1kHz or more away, even when the guy is sending only 10 WPM.

I'd like to agree with you, but I can't change how the system works. I wish I could because the bands would be much cleaner and we would not need to shape the waveform of the rise and fall. All we would need to do is turn the keyer speed down.

Unfortunately CW transmitters and receivers do not behave that way, and we have to set the rise and fall times and shape carefully to avoid adjacent channel keyclicks.

It was somewhere around the 1900's we learned this, but like many core skills we have forgotten the basics.

73 Tom


 
RE: Bandwidth versus Keying Speed  
by W6TH on May 27, 2007 Mail this to a friend!
.

Very interesting discussion brother hams, but remember this, when you qso me, remember to run a pure square wave and make that keying as hard as you can as it certainly makes good copy for my head at 50 to 70 wpm.

Guess you can't teach an old dog new tricks.

73, W6TH

.:
 
RE: Bandwidth versus Keying Speed  
by AA4PB on May 27, 2007 Mail this to a friend!
Tom, how does the CW bandwidth issue compare with bandwidth of other data modes (FSK for example)? I think that is part of the confusion. We are accustomed to thinking in terms of a higher signaling rate requiring greater bandwidth and trying to apply that to CW. I don't think you are implying that 300 baud packet requires the same bandwidth as 1200 baud packet, for example.

 
RE: Bandwidth versus Keying Speed  
by VA3NR on May 27, 2007 Mail this to a friend!
I have a question on the mathematical analysis: I think the analysis assumes periodic pulse trains at the two speeds. i.e a string of dits. How does the analysis change if the transitions instead occur at random times? i.e. dashes, spaces between characters, and spaces between words are NOT integer multiples of the dot length. In fact they are not even constant - they vary throughout the transmission.

Thanks, I appreciate the presentation and discussion. Fourier study was long time ago for me and I think I purged it immediately upon graduation.

73, Chris VA3NR.
 
RE: Bandwidth versus Keying Speed  
by SM0AOM on May 27, 2007 Mail this to a friend!
For those that can read German, the ITU point of view
regarding the relation between A1A telegraphy keying rates and occupied or necessary bandwidths is elaborated on http://www.qsl.net/dk5ke/a1a.html#signal

I would be most surprised if the international
radio engineering community should have been wrong all the time on this subject.

The "key-clicks" or spurious emissions that poorly engineered equipment can generate are a separate subject.

73/

Karl-Arne
SM0AOM



 
RE: Bandwidth versus Keying Speed  
by W6TH on May 27, 2007 Mail this to a friend!
.
The "key-clicks" or spurious emissions that poorly engineered equipment can generate are a separate subject.
..............................................
This I agree.

Actually it is not poor engineering and can be overlooked. All it amounts to is time constants of a capacitor and a resistor.

On my Icom 756 Pro III, I have tried the 2, 4, 6, and the 8 ms for wave shaping and on the actual testing on the air, the operators have not by ear noticed any change. All agreed it was clean and smooth.

With my two Icom 718 radios, I have yet to have a complaint with the one exception, at high speed keying the receiving operators wanted the semi breakin keying.
This do to the shortening of dits and dahs.

...Sometimes hams get carried away...

On cw, we do not need the 3 Khz bandwidth and the use of filters can shorten the bandwidth, fiddle dee dum.

.:
 
Bandwidth versus Keying Speed  
by K5MC on May 27, 2007 Mail this to a friend!
I appreciate very much the nice comments from a number of hams regarding my article. Now I would like to respond to some comments from VA3NR and SM0AOM.

I chose a long string of dits as the keying waveform (a so-called deterministic signal) so that it would be "reasonably easy" to calculate the power bandwidth of the resulting CW signal. The keying waveform that VA3NR mentioned is a true random signal that cannot be described as a function of time and it is impossible to find its Fourier transform. The approach taken in the signal analysis world is to determine the autocorrelation function of the random signal from its statistical information; from that one can find the power spectral density (PSD) function. Finally, the power contributed by the spectral components over a specific frequency interval can be found by integrating the PSD over that frequency interval. The most difficult part in this process, as far as I'm concerned, is to determine the autocorrelation function of a random keying waveform. Although I have not pursued the professional literature on this specific topic, I would be pleasantly surprised if anybody has ever nailed down the autocorrelation function of a random Morse code keying waveform.

Assuming a long string of dits as the keying waveform pretty much assures that the "worst-case" power bandwidth is found for a given code speed and assumed rise/fall characteristics. For example, in my article I reported that the 99.1% power bandwidth of a CW transmitter using sinusoidal keying (5-ms rise/fall times) is 150 Hz at 30 wpm. The 99.1% power bandwidth of that transmitter sending a random message at 30-wpm would have to be somewhat less than 150 Hz.

Regarding SM0AOM's comments, unfortunately I cannot read German. (There's probably an English version of those ITU rules around somewhere, but I haven't looked for it.) I suspect that the ITU rules are an elaboration of what we find in Part 97, however. The FCC distinguishes between "spurious" emissions (such as harmonics), "out-of band" emissions (such as key clicks) and "necessary" bandwidth.

By the way, the so-called "necessary" bandwidth is essentially a "legal" definition in my view; it certainly isn't an engineering (that is, mathematically precise) definition compared to occupied bandwidth, power bandwidth, absolute bandwidth, null-to-null bandwidth, equivalent noise bandwidth, and several others discussed in the engineering literature. Part 2 of the FCC rules (which I referenced in my article) includes a table of necessary bandwidths for a variety of signals.

It is also interesting to note that the definition of bandwidth found in 97.3 is, in essence, the 99.75% power bandwidth. The definition actually says the following: "Bandwidth. The width of a frequency band outside of which the mean power of the transmitted signal is attenuated at least 26 dB below the mean power of the transmitted signal within the band." This is the 99.75% (that is, 0.9975) power bandwidth because

10 log (1-0.9975)/1 = 10 log 0.0025/1 = -26.02 dB

The 99.75% power bandwidth, of course, will be somewhat larger than the 99% power bandwidth (which is, in essence, the FCC's definition of occupied bandwidth) for a given signal.

In closing this round of my comments, I will once again attempt to point out to W8JI (as I did in my original article) that the concept of power bandwidth does not say that the key clicks heard from a poorly designed CW transmitter are reduced in strength if the keying speed is reduced. Some people try to read that conclusion into the concept of power bandwidth (along with the general subject of Fourier analysis!), but they are simply misreading the information provided by the power bandwidth. The power bandwidth represents the time average values of the powers contributed by the various frequency components of the CW signal. You can be sure that, regardless of what W8JI or some others might say, the "power" bandwidth (and the "occupied" bandwidth as defined by the FCC) of a CW signal does definitely vary with the keying speed as I reported in my article.

73, K5MC
 
RE: Bandwidth versus Keying Speed  
by W6TH on May 27, 2007 Mail this to a friend!
.
K5MC,

You can be sure that, regardless of what W8JI or some others might say, the "power" bandwidth (and the "occupied" bandwidth as defined by the FCC) of a CW signal does definitely vary with the keying speed as I reported in my article.
..................................................

Thanks Mickey and looking back quite a few years, I have remembered somewhat the same as above mentioned.

.......I am on your side with this one, thanks for the post and the math that finally convinced me...Don't be too shy and come visit us again.

73, W6TH
.:
 
RE: Bandwidth versus Keying Speed  
by W8JI on May 27, 2007 Mail this to a friend!
Well in closing all I can say is there are people who willtake the time to reason through the problem and understand it, or to actually perform an experiment to confirm their understanding.

In the other camp there are those who will misapply a good formula and make it apply to something it does not actually apply to.

For example our friend from Sweden says it is a transmitter "defect". But there are no transmitters I've ever seen that readjust the rise and fall times to fit the very minimum bandwidth theory dictates. I doubt anyone would want a transmitter that sounded softer and softer as speed was slowed, or that changed rise and fall times on every dot and again when a dash came along.

Indeed if we set that as the standard for a "good design", so the bandwidth actually does what a few people claim and changes with speed, then every transmitter in the world is defective.


Until the people who are misapplying the formula actually take the time to reason through the problem or get off their duffs and do a simple experiment almost any novice could do.... there will be no meeting of the minds.

73 Tom

 
RE: Bandwidth versus Keying Speed  
by W9AC on May 27, 2007 Mail this to a friend!
Mickey:

I believe you are incorrectly mixing occupied bandwidth with time.

Certainly, the amount of total time of occupied bandwidth is greater under higher WPM conditions. Why? Consider a ten-second period of keying at slow and fast WPM rates. At very slow speed, the number of rise/decay sequences may only be a fraction of rise/fall sequences at a higher WPM rate.

If I key a transmitter once during a ten-second period, there is one bandwidth-consuming rise interval and exactly one bandwidth-consuming decay interval. By contrast, perhaps 30 or more rise/decay changes occur during that same ten second period under higher WPM conditions -- but the amount of occupied bandwidth remains exactly the same in each case.

True, there may be a perception of higher occupied bandwidth with the higher WPM rate -- only because banwidth-consuming transitions are occuring more often over any given time period. However, as others have shown, the bandwidth of a pure CW signal is developed during the transition between zero and full delivered power -- and again at the transition back to zero.

The repetitions associated with keying speed have no consequence on bandwidth except perhaps as some keying extreme when keying becomes so fast that the keying rate is actually faster than the rise/decay time of the waveform; a pretty unlikely scenario.

Paul, W9AC

 
Bandwidth versus Keying Speed  
by W1YW on May 27, 2007 Mail this to a friend!
"... welcome anyone with a signal analysis/communications background to check my mathematics. The signal analysis that I discussed in my article (99.1% power bandwidth!) is representative of what a good junior or senior electrical engineering student is able to do after completing a typical signal analysis/communications course. I should know this because I'm an electrical engineering professor and I've taught such courses for over 20 years now"

-------------------------

Looks good. Thanks for contributing.

73,
Chip W1YW
(now retired from BU)
 
RE: Bandwidth versus Keying Speed  
by W9AC on May 27, 2007 Mail this to a friend!
I should clarify my previous statement in that the application of time to bandwidth is necessary but it's the way time and bandwidth are being applied in the article that yield incorrect results.

Paul, W9AC
 
Bandwidth versus Keying Speed  
by N0AH on May 27, 2007 Mail this to a friend!
I agree with the accomplished MFJ amateur radio operator..........just look at 160M. Acclaimed DXers will jump all over your attempt to DX on the topband next to their frequencies served (at table 10. 1.823MHz)You better make sure to make something perfect which cannot be made perfect. And adjusting your speed to keep within a given bandwidth is stupid. Now turning off your amplifier, (Negative QRO for you newbies), that will keep you within bandwidth more than speed. Wy no one has brought this part of the equation up is par for this course- . I still really like the article. I have it printed off and in the binder.
 
Bandwidth versus Keying Speed  
by K5MC on May 27, 2007 Mail this to a friend!
The positive feedback from both W6TH and W1YW is gratefully acknowledged.

I just realized that I was rather sloppy in my last posting, however, with my algebra in demonstrating that the bandwidth definition in Part 97.3 of the FCC rules is equivalent to the 99.75% power bandwidth. Here's a better "proof" of that statement:

10 log (Po/Pi) = -26 dB

where Po is the mean (average) power in the "outside" frequency band of the signal and Pi is the mean power in the "inside" (within the) frequency band of the signal.

Solving the equation above by dividing both sides by 10 and then taking the antilog of both sides we have

Po/Pi = 10^(-2.6) = 0.002512

Po = 0.002512 Pi

Pt = Po + Pi = 1.002512 Pi

where Pt is the total average power of the signal

Therefore, Pi = Pt/1.002512 = 0.997494 Pt. Thus, the average power of the transmitted signal within the band is very nearly 99.75% of the signal's total average power.

73, K5MC
 
RE: Bandwidth versus Keying Speed  
by AB0WR on May 27, 2007 Mail this to a friend!
For square pulses repeated at a specfic interval we can define two values.

"a" is the pulse width. T is the time measured from halfway between pulse 1 and pulse 2 to halfway between pulse 2 and pulse 3.

In essence, a/T is a measure of the duty cycle of the pulse train. If "a" is held constant and T goes up then the duty cycle gets less.

The Fourier serices coefficient "c" for such a series of pulses is defined as

(V)(a/T)[ sin(nwa/2) / (nwa/2) ]

where V is the amplitude of the pulse and w = 2pi/T

As T approaches infinity you sooner or later wind up with the inverse Fourier transform equation.

It would seem that this would mean that only your coefficient values would change, their relationship wouldn't. Thus your power bandwidth calculations would require the same number of terms giving you the same bandwidth. The power contained might not be the same.

tim ab0wr

 
RE: Bandwidth versus Keying Speed  
by SM0AOM on May 27, 2007 Mail this to a friend!
"But there are no transmitters I've ever seen that readjust the rise and fall times to fit the very minimum bandwidth theory dictates"

In fact there are such transmitters.

One that I have used myself is the Telefunken
S Steu 676 + Tg 676 exciter. It contains several rise/fall time options (realized as multi-pole low-pass filtering of the keying waveform), one of which is chosen for a given A1A keying rate. It does however not adjust its rise and fall time for the length of every signal element.

The description [1961]of this function in the transmitter quotes the CCIR Recommendation 230 from 1959, so the whole concept appears to have been well known already then by the professional and regulatory world.

Finally, I believe that the FCC 2.202 bandwidth calculations come straight out of the ITU Radio Regulations.

73/

Karl-Arne
SM0AOM
 
Bandwidth versus Keying Speed  
by W1YW on May 28, 2007 Mail this to a friend!
And adjusting your speed to keep within a given bandwidth is stupid.

----------------------

..amd yet the PHYSICS tells you the reality.

Actually, a related case comes up in SETI. It is presumed that narrow signal(s)will be transmitted at a very low bit rate, in part to keep the highest SNR: increasing bandwidth decreases the SNR for a given power.

The SNR will, in fact, decrease as your keying speed increases. Don't like that fact? Tough. And don't do moonbounce.

I am so grateful that W9AC put up a fun and informative piece, written for everyone to understand and enjoy--and refuses to be driven away just because he is smart, and worked hard to get that way.


73,
Chip W1YW
 
Bandwidth versus Keying Speed  
by W1YW on May 28, 2007 Mail this to a friend!
Apologies to K5MC--

Obviously the august article author; whereas W9AC is a cordial and worthwhile commenter.

Let's see if I get my call straight:-)

73,
Chip W1YW
 
RE: Bandwidth versus Keying Speed  
by W9OY on May 28, 2007 Mail this to a friend!
Paul writes:

"True, there may be a perception of higher occupied bandwidth with the higher WPM rate -- only because bandwidth-consuming transitions are occurring more often over any given time period. However, as others have shown, the bandwidth of a pure CW signal is developed during the transition between zero and full delivered power -- and again at the transition back to zero."

I find this statement a bit confusing. How is this perception realized? If a string of transitions are in fact causing this "perception" are you analyzing the wrong thing?

73 W9OY
 
RE: Bandwidth versus Keying Speed  
by VA3NR on May 28, 2007 Mail this to a friend!
It is the issue of time-averaging the power spectrum that’s leading to the different viewpoints. The length of time over which the power is averaged is subjective. The presentation uses a relatively large window, such that the (small) bandwidth during the constant amplitude portion pulls the average down vs. the (large) bandwidth during the transitions.

Time-averaging over long period is not useful method of looking at key clicks. Consider a transmitter sending wide clicks at 100wpm for 10 seconds but then going key-down and sending a steady carrier for 50 seconds. The calculated 1-minute time-average bandwidth would give appearance of relatively small bandwidth because most of the time the bandwidth was very narrow.

The math to prove it has long since left me, but I suspect the time average bandwidth would be directly related to the number of transitions in the time window. So for a given (long) window, and periodic keying waveform, higher speed gives larger average.

For looking at clicks, it would be more useful to use relatively small window for time averaging the spectrum. I saw FCC reg.s just mentions “mean power” and doesn’t specify time interval. There is some guidance in mean power definition in US Federal Standard 1037C:

“mean power (of a radio transmitter): The average power supplied to the antenna transmission line by a transmitter during an interval of time sufficiently long compared with the lowest frequency encountered in the modulation taken under normal operating conditions. [NTIA] [RR] (188) Note: Normally, a time of 0.1 second, during which the mean power is greatest, will be selected.”

I suspect if in the analysis, a window of only 0.1 second were used to average power, and the worst case throughout the pulse trains were selected, it would more effectively capture the clicks produced during the transitions. I suspect wpm speed would have little effect over range where there were equal number of transitions in the window.

73, Chris VA3NR

___
For those interested, definition of bandwidth for Cdn. Amateur is worded differently and doesn’t use mention average or mean power. From Industry Canada RIC-2: “The bandwidth of a signal shall be determined by measuring the frequency band occupied by that signal at a level that is 26 dB below the maximum amplitude of that signal.”
 
RE: Bandwidth versus Keying Speed  
by W9AC on May 28, 2007 Mail this to a friend!
"I find this statement a bit confusing. How is this perception realized? If a string of transitions are in fact causing this "perception" are you analyzing the wrong thing?"

Lee,

It's not that complicated. There is no "perception" being analyzed. More rise/decay transitions per unit of time will be more apparent to the listener.

Example: If someone sends a string of dits for ten seconds at 60 WPM from a transmitter generating moderate key clicks, and I listed to a weak DX station up a few hundred Hz, the interference caused by key clicks is more noticeable than locking down the key of the same transmitter for ten seconds where there is one CW rise period and one decay period. More rise/decay transitions per unit of time are more noticeable to a listener. This is the "perception" I spoke of earlier.

However, in this example, the occupied bandwidth remains the same whether the keys clicks are generated at 60WPM or 0.5 WPM.

Paul, W9AC
 
Bandwidth versus Keying Speed  
by K5MC on May 28, 2007 Mail this to a friend!
I believe AB0WR has been reviewing some of his old EE textbooks! Tim's mathematical posting is the classic analysis of a train of rectangular pulses of amplitude V and duration "a" seconds, recurring periodically every T seconds. (I used the term "square-wave" rather than "rectangular" in my article.) Because I have my latest edition of Hayt and Kemmerly (one of the most classic EE circuits books around) handy, I will simply "borrow" some observations directly from it. The bandwidth of a filter that's designed to pass these periodic pulses is a function of the pulse width but not of the pulse period. The "required" bandwidth is approximately 1/a Hz. (This turns out to be essentially the "first null" bandwidth.) Because I assumed that my keying waveform was a "string of dits" having a constant duty cycle of 50%, both a and T change proportionally with speed such that a/T = 0.5. Therefore, I found that the power bandwidth varies directly with the speed in the case of square-wave (rectangular) keying, which is exactly consistent with the theory.

SM0AOM's comment about some CW transmitters from 45 years ago having variable rise/fall characteristics is very interesting. I am not surprised to learn that that is exactly the case. There are obviously some additional issues involved regarding the rise/fall characteristics of a CW signal versus speed when a human operator is involved (for example, "harder" keying to combat QSB/QRN), but if we ignore those issues, it would be desirable to increase the rise/fall times as we decrease our sending speed. Maintaining constant rise/fall characteristics regardless of speed is certainly not the norm in modern digital communication systems. (By the way, I've looked at the keying envelope generated by my Orion II. It looks approximately sinusoidal to me. Although the software setting says 8 ms, the rise/fall times look about 5 ms according to the scope.)

As W1YW as pointed out, we can improve our S/N ratio by slowing down. QRSS is an extreme example of this fact. Indeed, the fundamental relationships between bandwidth, S/N ratio, and channel capacity as expressed by Shannon's equation are quite fascinating!

73, K5MC
 
Bandwidth versus Keying Speed  
by K5MC on May 28, 2007 Mail this to a friend!
VA3NR makes some very interesting comments. Fourier analysis can be misleading when used to study signal transients. As I pointed out earlier, the frequency information of a signal calculated by the classical Fourier transform is an average over the entire time duration of the signal. If there is a local transient over some small interval of time in the lifetime of the signal (such as the rise/fall times of a single keying pulse having a relatively long total time duration), the transient will contribute to the Fourier transform but its location on the time axis will be lost.

The "short-time" Fourier transform is one attempt to overcome this limitation, but a more recent mathematical approach to studying signal transients is "wavelet" analysis. Rather than using everlasting sinusoids, the wavelet functions are "local" both in time and frequency. There are many different families of wavelet functions, however, and choosing the most appropriate one to use for a specific signal isn't usually a trivial matter. Perhaps some day a manufacturer will develop a "wavelet" analyzer to study signal transients, but as far as I know, no such instrument is readily available and wavelet analysis remains more of a research tool. (Studying the transients generated by a variety of CW keying waveforms using wavelets would probably make an interesting research topic for my next graduate student!)

At times Fourier analysis strikes me as a very artificial way to study real signals. For example, an orchestra has a finite number of instruments, each of which that often starts and stops and starts again, with varying amplitudes and frequencies, while playing a particular piece of music over some particular time interval a < t < b. A Fourier transform can be determined for that particular piece of music. In effect, the Fourier "orchestra" consists of an infinite number of instruments (sinusoids), each one playing a very monotonous tone of constant amplitude and frequency, starting from time equal to negative infinity and continuing forever. The frequency of each instrument is infinitesimally smaller or larger than that of its adjacent instruments (continuous line spectrum). The amplitudes and phases of these sinusoids are such that they add up to the particular piece of music from a < t < b and add up to zero at all other times! Lathi [1] refers to this as the "marvelous balancing act" of Fourier transforms. It amazes me that Fourier analysis proves to be such a useful tool in the study of real signals and systems.

[1] B.P. Lathi, Modern Digital and Analog Communication Systems, 3rd ed., Oxford University Press, 1998.

73, K5MC
 
RE: Bandwidth versus Keying Speed  
by W9OY on May 28, 2007 Mail this to a friend!
Paul

My point was that analyzing a transmitted signal is not quite the same as analyzing a received signal.

Guess I was a bit too subtle

73
 
RE: Bandwidth versus Keying Speed  
by AB0WR on May 28, 2007 Mail this to a friend!
k5mc:"The "short-time" Fourier transform is one attempt to overcome this limitation, but a more recent mathematical approach to studying signal transients is "wavelet" analysis"

Are there any reasonably priced books you would recommend on this? This must be an analysis tool developed after I left school.

tim ab0wr
 
Bandwidth versus Keying Speed  
by K4GLM on May 28, 2007 Mail this to a friend!
Nice work, Mickey
I think of the phenomenon as adding and subtracting the digital signal to the carrier. This produces sums and differences, that are greater when the digital signal is greater; hence more bandwidth.
I believe Claude Elwood Shannon mathematically defined this with Shannon's theorem. (Not me, maybe a cousin or something...)
Shannon Boal K4GLM
 
Ain't seen nothing yet!  
by N4QA on May 29, 2007 Mail this to a friend!
And, if the no-coders of this world are frightened of communication via on-off keying of sinewaves, just wait 'til someone attempts to clue them in to the intricacies of the generation, modulation, transmission etc of the human voice!

CW forever!

72.
Bill, N4QA
 
Bandwidth versus Keying Speed  
by K5MC on May 29, 2007 Mail this to a friend!
In response to AB0WR's question, two books I have at home that discuss short-time Fourier transforms are:

System Analysis and Signal Processing by Philip Denbigh (Addison-Wesley, 1998, ISBN 0-201-17860-5)
Signals and Systems by Simon Haykin and Barry Van Veen (Wiley, 2005, ISBN 0-471-70789-9)

I will look in my office at school later this week for some other books. Many of the books that discuss fast Fourier transforms (FFTs) may also include a discussion of short-time Fourier transforms.

As Denbigh points out in his book, to analyze a signal whose frequency content changes with time, the waveform is divided up into segments. Each of these segments is analyzed separately by means of the FFT to give a "short-time" Fourier transform (STFT) and then the resulting spectra are displayed side by side to generate a "spectrogram." Speech is probably the mos