2. Since its very clear that height for a dipole affects the take off angle, does the laws of reciprocity apply? In other words, does it also affect RX at the same angle? In other other words, if I were to simulate a dipole at 33 feet and has a peak gain of 6db at 20 degrees TX does this mean RX would have a similar pattern (I understand that there will be no gain)? In other other other words is my RX affected by height for DX as much as TX.
To give some context as to why I am asking:
I ask I can not hear anything further than New Mexico West, Brazil South, Almost NOTHING North, Lithania Eastern Europe - this is on 20M and of course 10m is much better and I understand why but again is it just because TX is overall better due to gain?... so, I am focusing on 20M for the question.
Seeing as nobody has answered this:
Yes, the laws of reciprocity apply. Gains for TX are also gains for RX. If your dipole is half wavelength or lower, you'll hear stations up to 3000 miles well but anything further than that will be quite poor compared to getting the dipole a wavelength high.
As for what you can hear.....
Go to this website and generate an azimuthal map of the world - it'll look very different to a normal map but it actually shows the shortest paths to places and is what you use to aim a beam antenna:http://ns6t.net/azimuth/azimuth.html
Now print it out and draw a line on it where your dipole is pointing. Now draw an oval the shape of a peanut centered on the middle of the map and at right angles to that line. Make it so the ends of the long side of the peanut go to about halfway out from the center.
You'll end up with something like this:http://tinyurl.com/btju5gv
Anything inside that peanut shape is roughly the area you'll cover well with your 20m dipole at 30ft. It will cover outside that but it'll be hard work and mostly strong stations you hear.