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Author Topic: Does the formula change?  (Read 1168 times)
KB1PTR
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Posts: 10




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« on: January 07, 2012, 02:39:56 PM »

I believe the 468/ formula for a dipole considers the use of 14ga wire. I'm making up one using 10ga wire. Do I need to make any adjustments? If so what would it be?   Thanks
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WB6BYU
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Posts: 13285




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« Reply #1 on: January 07, 2012, 02:48:33 PM »

Here is a good summary of why the traditional formula is only an approximation anyway:

http://www.cebik.com/content/a10/wire/cut.html

You also have to consider any insulation on the wire, the height above ground, and
the ground characteristics in addition to the wire diameter.
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KB1PTR
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Posts: 10




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« Reply #2 on: January 07, 2012, 03:02:56 PM »

Thanks for the link. Will give it the once over.
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NA0AA
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Posts: 1042




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« Reply #3 on: January 07, 2012, 08:22:12 PM »

No, height above ground and ground itself are more important than any wire size that is practical at HF.

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K4FMH
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Posts: 255




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« Reply #4 on: January 09, 2012, 07:11:38 PM »

Here's a link to a short video explanation of the 468 parameter as only a real-world approximation:

http://www.youtube.com/watch?v=FtvJttfub9w

73 de Frank K4FMH
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AD6KA
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Posts: 2237




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« Reply #5 on: January 09, 2012, 07:36:11 PM »

Like an old timer I used to know liked to say:
"Stop looking for fly shit in pepper!"

Figure the length the traditional way, cut it
long, put it up and trim it till it's where you like it.

Of COURSE it's nice to know the theory behind
formulas and phenomena,
but don't get bogged
down in it for a simple dipole.....IMHO. YMMV.

Good luck with your antenna!
We'll be listening for ya!
73, Ken  AD6KA
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