How would perform a twisted military wire (I believe it's characteristic impedance is about 100 ohms ) feedline and then opened as a doublet? Would the feedline still be low loss or a 450 ladder line is better?
“Better” in what regard?
It certainly will “work” if that is what you have handy.
Losses likely will be higher than for 450 ohm line,
but may be a reasonable choice if the light weight and
small size are important to you.
There are three main sources of loss in a transmission
line: the wire diameter, the insulation type, and
the type of metal used in the wire.
For copper wires using polyethylene insulation, the
effective resistance of the wires is often the limiting
factor. Larger diameter wires have less resistance.
However, there is also the impedance of the line
to consider: a higher impedance line tends to have
higher voltage and lower current (when averaged
over the length), and the lower current reduces
losses in the wire.
While polyethylene has low losses, PVC and many
other plastics not designed for RF use can increase
losses, sometimes significantly. This often is a
problem when using speaker wire or zip cord.
The losses in magnetic steel increase with frequency,
as at each reversal of current some power gets used
in reversing the magnetic field of the wire. Stainless
steel, on the other hand, isn’t as affected as much
(depending on the type).
With Copper-Clad steel, the thickness of the copper
is important: it has to be several times the skin
depth to keep most of the current in the copper
instead of in the steel. As a result, losses may
actually increase as the frequency is lowered
below a certain frequency. Stranded copper-clad is
even more lossy, as the effective copper thickness
is just that of one of the strands.
So there are lots of factors.
I would expect it to have higher losses than full-
sized 450 ohm types, especially if it has steel
conductors.
Fortunately, it isn’t too difficult to check the
cable loss at different frequencies if you have
an antenna analyzer or VNA. Stretch out a
length of cable, short the far end, and find
the resistance at those frequencies where
it drops to a low value. Then open the far end
and take a second set of measurements (which
will be at different frequencies).
The cable loss can then be determined at each
of the frequencies
the method described here.
I have a basic MFJ tuner with an internal voltage 1:4 balun. Given the rather low impedance of the feedline would you prefer to use that internal balun or would you use a common mode filter between the tuner and the feedline or the common mode filter between the tuner and the transceiver?
I would nearly always choose to use a 1 : 1 current
balun (feedline choke) between the feedline and
the tuner. The tuner likely is a T network type, and
they tend to be more efficient matching higher
impedances (up to 1000 ohms or so) than lower
ones (under 50 ohms). Using a 4 : 1 balun at
that point we’ll reduce the impedance the tuner
must match.
Are you planning on using this antenna for as a
single band dipole, or as a doublet on multiple
bands? If the impedance is really close to 100
ohms (it may be higher with small wires) then
I’ve had good results using a flattened loop
with
a 200 ohm feedpoint impedance in place
of the dipole, and a 1/4 wave matching of 100
ohm line as a matching section. The loop can
be erected in the same manner as a horizontal
dipole, and the tie points at the corners adjusted
match the exact line impedance if desired.
Note, however, that small speaker cable is
often around 140-150 ohms, and the loop
impedance can’t be raised high to match
with such lines.