The answer is not so simple.
To accurately calculate the expected battery life you need to know the current draw on transmit. Unfortunately, the owner's manual doesn't give this information.
We can make a guess though. The current draw will be 5W /12V x efficiency. We don't know the efficiency but let's assume 50%. That is, your radio will draw twice as much power from the battery as goes out the antenna.
So: I = 5W/12V x 2 = .833 A (or 833 mA)
If you transmit for 2 minutes, that's 1/30th of an hour.
So your power consumption would be 833 mA x 1/30H = 27.8 mAH
Your battery pack is rated at 1200 mAH so:
1200mAH/27.8mA = 43 two minute transmissions (or 1.4 Hours continuous)
Experience tells me that no HT is going to put out 5W for 1 1/2 hours on one battery, so I assume that my guess for efficiency is way off.
Now, when I estimated 50%, I was only figuring the power consumption of the final amplifier. The battery also has to run the frequency synthesizer and driver stages.
Do you really need 5W? A local event in a park or some other situation where the radius of communications is less than 1 mile, could probably be covered with 1W or less. Also, a 2 minute transmission seems very long. Perhaps your answer is a modification in your operating habits.
I hope this helps.
73, Jerry