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Author Topic: 40m inverted delta loop  (Read 1094 times)
WB6BYU
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Posts: 17189




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« Reply #15 on: December 07, 2017, 08:44:50 AM »

The location of the feedpoint on the loop determines the current distribution around it.  When the
feedpoint is open circuited, that will be a point of minimum current, and the maximum currents
(which affect the radiation pattern and polarization) will be determined by that.

When the loop is fed at that point, the current will be maximum at the opposite point of the loop
(half way around it, for any loop) and at the feedpoint (for a full wave loop.)

If the dipole is inducing current into the loop with a shorted feedpoint, the current distribution
will probably be centered on the middle of the dipole, which will be different than either of the
other two cases.

That's why changing the load at the end of the feedline to the loop may change the interaction
between the two antennas when the dipole is fed, as it changes the current distribution in the loop.
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